Plastering: – This work activity means a thin layer of mortar, applied over the Wall & ceiling masonry, which it acts like a damp-proof coat over the masonry work
Mortar: – Is a mixture of Cement (or) Lime, sand & water, which is used in masonry work in construction to fill the gaps between the bricks and blocks.
How to Calculate Cement, and Sand Quantities in Plastering Work
For Example size of Wall
Length of Wall (L) – 50m, Height of Wall (H) – 4.0m,
Thickness of Plaster (T) – 12 mm (Inner Wall)
STANDART PLASTER THICKNESS
| Plastering Area | Thickness of Plaster |
| Inner Plaster Work | 10-12 mm |
| Outer Plaster Work | 15-20 mm |
| Ceiling Plaster Work | 6-8 mm |
Plaster Area =Length × Height
Plaster Area =50×4 =200.00m2
Volume of Mortar = Plaster Area x Plaster Thickness in meter
Volume of Mortar = 200.00 x 0.012 = 2.40 mᶟ
If Ratio of Plaster is – 1:6 , Which Means 1% of Cement & 6 % of Sand
FORMULA TO FIND THE QUANTITIES OF CEMENT, SAND IS
Formula = \frac{Dry Volume of mortar * Volume of mortar * Ratio of (Cement /Sand) }{Total Ratio (Cement + Sand)}
If it is Outer Wall Dry Volume of mortar -1.33mᶟ
Volume of Mortar -2.4 mᶟ
Ratio of Cement = 1, Ratio of Sand =6, , Total Ratio (1+ 6) = 7
Required Quantity of Cement & Sand in 2.4 mᶟ Plastering Work is
Cement = \frac{1.33 * 2.4 * 1}{ 1 + 6} = 0.456 mᶟ
Sand= \frac{1.33 * 2.4* 6}{ 1 + 6} = 2.736 mᶟ
Which Means 1:6 mortar Ratio of Plastering Works Required,
Cement – 0.456 mᶟ / 1mᶟ of cement Equal to 29 bags of Cement,
So, 0.456x 29 = 13.224 Bags of Cement is required
1 Bag of cement to is Equal to 50Kg, So 50 x 13.224 =661.20 kg Cement Required
Sand – 2.736 mᶟ / 1mᶟ equal to 35.31 cu.ft / cubic foot / ftᶟ
So, 2.736 x 35.31 = 96.608 cu.ft / cubic foot Sand is required