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Basics of Engineering

How much Cement, Sand, Aggregate quantities required for 1 mᶟ of Concrete?

If, GRADE OF CONCRETE IS M-05, Ratio of M-05 Concrete – 1: 5: 10

CEMENT
: – Required Quantity of Cement is – 0.096 mᶟ,
29 bags of Cement required for 1mᶟ, So, 2.79 bags say 3 Bags of cement are required, 1 cement Bag is equal to 50 Kg So, 139.56 Kg is Cement is required. (Without any Wastage)

SAND : – Required Quantity of Sand is – 0.481 mᶟ / 16.993 ft (Without any Wastage)

AGGREGATE : – Required Quantity of Sand is – 0.963 mᶟ / 33.99 ft(Without any Wastage)

If, GRADE OF CONCRETE IS M-7.5, Ratio of M-7.5 Concrete – 1: 4: 8

CEMENT : – Required Quantity of Cement is – 0.118 mᶟ,29 bags of Cement required for 1mᶟ, So, 3.43 bags say 3.5 bags of cement are required, 1 cement Bag is equal to 50 Kg So, 171.169 Kg is Cement is required. (Without any Wastage)

SAND : – Required Quantity of Sand is – 0.474 mᶟ / 16.732 ft (Without any Wastage)

AGGREGATE : -Required Quantity of Sand is – 0.948 mᶟ / 33.46 ft(Without any Wastage)

If, GRADE OF CONCRETE IS M-10, Ratio of M-10 Concrete – 1: 3: 6

CEMENT : – Required Quantity of Cement is – 0.154 mᶟ,29 bags of Cement required for 1mᶟ, So, 4.46 bags say 4.50 bags of cement are required, 1 cement Bag is equal to 50 Kg So, 223.30 Kg is Cement is required. (Without any Wastage)

SAND : – Required Quantity of Sand is – 0.462 mᶟ / 16.313 ft (Without any Wastage)

AGGREGATE : –  Required Quantity of Sand is – 0.924 mᶟ / 32.63 ft(Without any Wastage)

If, GRADE OF CONCRETE IS M-15, Ratio of M-15 Concrete – 1: 2: 4

CEMENT : – Required Quantity of Cement is – 0.220 mᶟ,29 bags of Cement required for 1mᶟ, So, 6.38 bags say 6.50 bags of cement are required, 1 cement Bag is equal to 50 Kg So, 319.00 Kg is Cement is required. (Without any Wastage)

SAND : – Required Quantity of Sand is – 0.440 mᶟ / 15.536 ft (Without any Wastage)

AGGREGATE : –  Required Quantity of Sand is – 0.880 mᶟ / 31.07 ft(Without any Wastage)

If, GRADE OF CONCRETE IS M-20, Ratio of M-20 Concrete – 1: 1.5: 3

CEMENT : – Required Quantity of Cement is – 0.280 mᶟ,29 bags of Cement required for 1mᶟ, So, 8.12 bags say 8.50 bags of cement are required, 1 cement Bag is equal to 50 Kg So, 406.00 Kg is Cement is required. (Without any Wastage)

SAND : – Required Quantity of Sand is – 0.420 mᶟ / 14.830  ft (Without any Wastage)

AGGREGATE : –  Required Quantity of Sand is – 0.840 mᶟ / 29.66  ft(Without any Wastage)

If, GRADE OF CONCRETE IS M-25, Ratio of M-25 Concrete – 1: 1: 2

CEMENT : – Required Quantity of Cement is – 0.385 mᶟ,29 bags of Cement required for 1mᶟ, So, 11.16 bags Say 11.50 bags of cement are required, 1 cement Bag is equal to 50 Kg So, 558.25 Kg is Cement is required. (Without any Wastage)

SAND : – Required Quantity of Sand is – 0.385  mᶟ / 13.594  ft (Without any Wastage)

AGGREGATE : -Required Quantity of Sand is – 0.770 mᶟ / 27.16  ft(Without any Wastage)

Required Quantity of Cement, Sand, Aggregate for 1 mᶟ of Concrete

 Concrete Grade  Ratio Volume of Concrete  Required Cement Quantity  Required Sand Quantity  Required Aggregate Quantity 
 M-05  1:5:10 1 mᶟ  0.096 mᶟ / 2.79 Bags / 139.56 Kg 0.481 mᶟ/16.993 ftᶟ 0.963 mᶟ/33.99 ftᶟ
 M-7.5  1:4:8 1 mᶟ  0.118 mᶟ /3.43 Bags / 171.769 Kg 0.474 mᶟ/16.732 ftᶟ 0.948 mᶟ/33.46 ftᶟ
 M-10  1:3:6 1 mᶟ  0.154 mᶟ / 4.46 Bags / 223.30 Kg 0.462 mᶟ/ 16.313 ftᶟ 0.924 mᶟ/32.63  ftᶟ
 M-15  1:2:4 1 mᶟ  0.220 mᶟ / 6.38 Bags / 319.00 Kg 0.440 mᶟ/15.536 ftᶟ 0.880 mᶟ/31.07 ftᶟ
 M-20  1:1.5:3 1 mᶟ  0.280 mᶟ / 8.12 Bags / 406.00 Kg 0.420 mᶟ/ 14.830 ftᶟ 0.840 mᶟ/29.66  ftᶟ
 M-25  1:1:2 1 mᶟ  0.385 mᶟ /11.16 Bags / 558.250 Kg 0.385 mᶟ/13.594 ftᶟ 0.770 mᶟ/27.16 ftᶟ

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