Plastering: – This work activity means a thin layer of mortar, applied over the Wall & ceiling masonry, which it acts like a damp-proof coat over the masonry work

Mortar: – Is a mixture of Cement (or) Lime, sand & water, which is used in masonry work in construction to fill the gaps between the bricks and blocks.

**How to Calculate Cement, and Sand Quantities in Plastering Work**__For Example size of Wall__Length of Wall (L) – 50m, Height of Wall (H) – 4.0m,

Thickness of Plaster (T) – 12 mm (Inner Wall)

## STANDART PLASTER THICKNESS

Plastering Area | Thickness of Plaster |

Inner Plaster Work | 10-12 mm |

Outer Plaster Work | 15-20 mm |

Ceiling Plaster Work | 6-8 mm |

Plaster Area =Length × Height

Plaster Area =50×4 =200.00m

^{2}

^{}Volume of Mortar = Plaster Area x Plaster Thickness in meter

Volume of Mortar = 200.00 x 0.012 = 2.40 mᶟ

*If Ratio of Plaster is – 1:6 , Which Means 1% of Cement & 6 % of Sand*

**FORMULA TO FIND THE QUANTITIES OF CEMENT, SAND IS**Formula = \frac{Dry Volume of mortar * Volume of mortar * Ratio of (Cement /Sand) }{Total Ratio (Cement + Sand)}

If it is Outer Wall Dry Volume of mortar -1.33mᶟ

Volume of Mortar -2.4 mᶟ

Ratio of Cement = 1, Ratio of Sand =6, , Total Ratio (1+ 6) = 7

**Required Quantity of Cement & Sand in 2.4 mᶟ Plastering Work is**Cement = \frac{1.33 * 2.4 * 1}{ 1 + 6} = 0.456 mᶟ

Sand= \frac{1.33 * 2.4* 6}{ 1 + 6} = 2.736 mᶟ

Which Means 1:6 mortar Ratio of Plastering Works Required,

**Cement – 0.456 mᶟ / 1mᶟ of cement Equal to 29 bags of Cement,So, 0.456x 29 = 13.224 Bags of Cement is required1 Bag of cement to is Equal to 50Kg, So 50 x 13.224 =661.20 kg Cement RequiredSand – 2.736 mᶟ / 1mᶟ equal to 35.31 cu.ft / cubic foot / ftᶟSo, 2.736 x 35.31 = 96.608 cu.ft / cubic foot Sand is required**

Thank you for the learning guidelines.

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